Graph y 3/2x-1
WebJul 19, 2024 · This is a linear equation and will have a linear graph of straight line. The easier way to plot a linear graph is to find the x and y intercepts of the given equation. y … WebStep 3.1. Replace the variable with in the expression. Step 3.2. Simplify the result. Tap for more steps... Step 3.2.1. Raise to the power of . Step 3.2.2. The final answer is . ...
Graph y 3/2x-1
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WebExplanation: The standard form for the equation of a parabola is y = a2 +bx +c ... How do you graph y = x2 −2x+ 2 ? Set up a column for x and y (the expression). Calculate y for each x, then plot the points on graph paper. Explanation: Generating the points to plot is a necessary first step, whether you do it by ... Web2. The graph of y > 3/4x - 2 is a dashed line. 4. One solution to the inequality is (0, 0). 5. The graph intercepts the y-axis at (0, -2). Which is the graph of the linear inequality 2x - 3y < 12? C. Graph Three (dashed line shaded above) The solutions to the inequality y ≤ 2x − 4 are shaded on the graph.
WebQuestion 128348: y=3/2x-1 Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website! ... Since this tells us that the y-intercept is … WebApr 3, 2024 · The first thing we are going to do for this case is to rewrite the function. We have then: y = 3 ^ (2x) We evaluate the points: For (1,9): y = 3 ^ (2 * 1) y = 3 ^ (2) y = 9 The point belongs to the function. For (1/2, 3): y = 3 ^ (2 * (1/2)) y = 3 ^ (1) y = 3 The point belongs to the function. For (-1, -9): y = 3 ^ (2 * (- 1)) y = 3 ^ (- 2) y = 1/9
WebExpert Answer. To graph the function y=3cos (1/2x-2π)-1, we can use the following steps:Explanation:Identify the amplitude: The amplitude of the function is 3, …. View the full answer. WebTo get this in slope intercept form, subtract 4x to get 3y=-4x+6. To get rid of the coefficient of 3, we have to divide ALL TERMS by 3 to get 3/3y = 4/3 x + 6/3 or y=4/3x + 2. If you do not divide all terms on the other side, you will not get an equivalent equation. Example: suppose you say 10 = 6 + 4.
WebNotice that the equation is already in y y -intercept form so we can graph it by starting at the y y -intercept of 3 3, and then going up 1 1 and to the right 2 2 from there. Next, let's graph the second equation \greenE {y=x+1} y = x +1 as well. There is exactly one point where the graphs intersect. This is the solution to the system of equations.
WebTo graph an equation, enter an equation that starts with "y=" or "x=". Here are some examples: y=2x^2+1 , y=3x-1 , x=5 , x=y^2 . To graph a point, enter an ordered pair with the x-coordinate and y-coordinate separated by a comma, e.g., (3,4) . To graph two objects, simply place a semicolon between the two commands, e.g., y=2x^2+1; y=3x-1 . first presbyterian church lake charles laWebFree Pre-Algebra, Algebra, Trigonometry, Calculus, Geometry, Statistics and Chemistry calculators step-by-step first presbyterian church lakelandWebGraph y-1=(x-3)^2. Step 1. Find the properties of the given parabola. Tap for more steps... Step 1.1. Add to both sides of the equation. Step 1.2. Use the vertex form, , to determine … first presbyterian church lawrence kansasWebThe equation indicates it is a line.Solve for the intersection of the line with the axes. This is one of the several ways to graph a line. Explanation: From the given: … first presbyterian church lancaster ohWebA: We need to solve number puzzle problem. Q: This is the wrong answer, please give me the correct answer. Q: Refer to the vectors u₁ to ug. -0-0-0-0-0-0-0-0 U4 = -5, 45 = 1 46 = 5, 47 = 3 (b) -5 (c) = 1 U2 = 1…. A: we have given vectors we need to find the distance between the mentioned vector. first presbyterian church lawton okWebIf not, you could also think of it as taking any y, the x coordinate =1, so pick any two y such as 2 and 3. Since you know x always equal 1, then you get the two points (1,2) and (1,3). If you graph the line through these two points, You will see that you get the vertical line going through the point (1,0). first presbyterian church learning centerWebIn order to graph a function, you have to have it in vertex form; a (x-d)² + c <---- Basic Form. Example: (x-3)² + 3. Since there's no a, you don't have to worry about flipping on the x axis and compressing or stretchign the function. Now we look at d. d = -3. In order to find the zeros of the function, x must equal 3. first presbyterian church las cruces nm